Statistics / Counting

Permutation and Combination Calculator (nPr, nCr)

Count the ways to choose r items from n, as ordered permutations (nPr) and unordered combinations (nCr), with or without repetition, as exact whole numbers.

Permutation and Combination Calculator (nPr, nCr): Permutations count ordered choices: nPr = n! ÷ (n − r)!; picking first, second, and third place from 10 runners gives 10 × 9 × 8 = 720. Combinations ignore order: nCr = n! ÷ (r! (n − r)!); any 3 of 10 gives 720 ÷ 6 = 120. With repetition, ordered choices number nʳ (a 4-digit PIN has 10⁴ = 10,000) and unordered ones C(n + r − 1, r). The arithmetic is exact, even for very large results. Runs 100% locally in your browser with zero server file uploads.

Runs
In your browser
Cost
Free · no sign-up
Availability
Ready to use
Permutation and combination calculatorLocal processing

Runs entirely in your browser

Permutations (nPr)720Order matters
Combinations (nCr)120Order does not matter

Permutations count ordered arrangements: nPr = n! ÷ (n − r)!, so choosing a gold, silver, and bronze winner from 10 runners gives 720. Combinations ignore order: nCr = n! ÷ (r! (n − r)!), so choosing any 3 of 10 gives 120. With repetition allowed, ordered choices number nʳ and unordered ones C(n + r − 1, r). Results are exact; very large ones are shown in scientific notation.

Worked examples

A committee of 4 from 12 people: C(12, 4) = 495. A chair, secretary, and treasurer from 12: P(12, 3) = 1,320. Arrangements of a 52-card deck: 52! ≈ 8.07 × 10⁶⁷.

To pick items at random instead of counting them, use the random number generator.

Factorials

n! multiplies all whole numbers from 1 to n: 5! = 120, 10! = 3,628,800, and 0! = 1 by definition, so that C(n, 0) = C(n, n) = 1.

Combinations appear as the coefficients of (a + b)ⁿ and in Pascal's triangle, where each number is the sum of the two above it.

How to use it

  1. Enter the total number of items, n.
  2. Enter how many are chosen, r, and tick if items can repeat.
  3. Read the number of permutations and combinations.

Privacy & limitations

Everything is calculated in your browser.

Related tools

Frequently asked questions

How do I know if order matters?

If swapping two chosen items gives a different outcome, such as positions in a race or digits in a code, use permutations; if not, such as a hand of cards or a committee, use combinations.

What are the odds of winning a 6 from 49 lottery?

There are C(49, 6) = 13,983,816 combinations, so one ticket has a 1 in 13,983,816 chance of the jackpot.

Why is a combination lock really a permutation?

Because the order of the numbers matters and they can repeat: a 3-wheel lock with digits 0–9 has 10³ = 1,000 settings.

Free tool · runs in your browser · no account required