{"{0} ÷ {1}":"{0} ÷ {1}","Average calculator":"Kalkulator rata-rata","Average of the two middle values":"Rata-rata dari dua nilai tengah","Cochran's formula, n₀ = z² × p(1 − p) ÷ e², gives the responses needed for a survey proportion to be within the margin of error e at the chosen confidence; 50% is the safe guess for p because it needs the most. For a small population N, the finite population correction n = n₀ ÷ (1 + (n₀ − 1) ÷ N) reduces it. It assumes a random sample; low response rates and biased samples are not fixed by size.":"Rumus Cochran, n₀ = z² × p(1 − p) ÷ e², memberikan jumlah respons yang diperlukan agar proporsi survei berada dalam margin of error e pada tingkat keyakinan yang dipilih; 50% adalah perkiraan aman untuk p karena memerlukan jumlah terbesar. Untuk populasi kecil N, koreksi populasi terbatas n = n₀ ÷ (1 + (n₀ − 1) ÷ N) menguranginya. Rumus ini mengasumsikan sampel acak; tingkat respons yang rendah dan sampel yang bias tidak dapat diperbaiki hanya dengan menambah ukurannya.","Combinations (nCr)":"Kombinasi (nCr)","Combinations with repetition":"Kombinasi dengan pengulangan","Confidence level":"Tingkat keyakinan","Each value counts in proportion to its weight: multiply each value by its weight, add the products, and divide by the total weight. Weights can be credits, hours, percentages that add to 100, or quantities; only their proportions matter.":"Setiap nilai dihitung sesuai proporsi bobotnya: kalikan setiap nilai dengan bobotnya, jumlahkan hasil perkaliannya, lalu bagi dengan total bobot. Bobot dapat berupa kredit, jam, persentase yang jumlahnya 100, atau kuantitas; yang penting hanya proporsinya.","Enter a margin of error between 0 and 50% and a proportion between 0 and 100%.":"Masukkan margin of error antara 0 dan 50% serta proporsi antara 0 dan 100%.","Enter at least one number.":"Masukkan setidaknya satu angka.","Enter the same number of values and weights ({0} values, {1} weights).":"Masukkan jumlah nilai dan bobot yang sama ({0} nilai, {1} bobot).","Enter whole numbers from 0 to 5,000.":"Masukkan bilangan bulat dari 0 hingga 5.000.","Expected proportion (%)":"Proporsi yang diharapkan (%)","Items can repeat":"Item dapat diulang","Items chosen (r)":"Item yang dipilih (r)","Margin of error (±%)":"Margin of error (±%)","Mean (average)":"Mean (rata-rata)","Median":"Median","Mode":"Modus","None (no value repeats)":"Tidak ada (tidak ada nilai yang berulang)","Numbers, separated by commas, spaces, or new lines":"Angka, dipisahkan dengan koma, spasi, atau baris baru","Order does not matter":"Urutan tidak berpengaruh","Order matters":"Urutan berpengaruh","Permutation and combination calculator":"Kalkulator permutasi dan kombinasi","Permutations (nPr)":"Permutasi (nPr)","Permutations count ordered arrangements: nPr = n! ÷ (n − r)!, so choosing a gold, silver, and bronze winner from 10 runners gives 720. Combinations ignore order: nCr = n! ÷ (r! (n − r)!), so choosing any 3 of 10 gives 120. With repetition allowed, ordered choices number nʳ and unordered ones C(n + r − 1, r). Results are exact; very large ones are shown in scientific notation.":"Permutasi menghitung susunan berurutan: nPr = n! ÷ (n − r)!, jadi memilih pemenang emas, perak, dan perunggu dari 10 pelari menghasilkan 720. Kombinasi mengabaikan urutan: nCr = n! ÷ (r! (n − r)!), jadi memilih 3 dari 10 menghasilkan 120. Jika pengulangan diperbolehkan, jumlah pilihan berurutan adalah nʳ dan pilihan tidak berurutan adalah C(n + r − 1, r). Hasilnya akurat; hasil yang sangat besar ditampilkan dalam notasi ilmiah.","Permutations with repetition (nʳ)":"Permutasi dengan pengulangan (nʳ)","Population size (optional)":"Ukuran populasi (opsional)","Range":"Rentang","Responses needed":"Respons yang diperlukan","Sample size calculator":"Kalkulator ukuran sampel","sample; population {0}":"sampel; populasi {0}","Share of the weight":"Proporsi bobot","Simple average, for comparison":"Rata-rata sederhana, sebagai perbandingan","Sorted: {0}":"Diurutkan: {0}","Standard deviation":"Simpangan baku","The mean adds the numbers and divides by how many there are; the median is the middle value when they are sorted, or the average of the two middle ones; the mode is the value that appears most often. A single very large or small value pulls the mean but not the median, which is why the median often describes incomes and house prices better.":"Mean menjumlahkan angka lalu membaginya dengan jumlah angka tersebut; median adalah nilai tengah setelah angka diurutkan, atau rata-rata dari dua nilai tengah; modus adalah nilai yang paling sering muncul. Satu nilai yang sangat besar atau kecil memengaruhi mean, tetapi tidak median. Karena itu, median sering kali lebih baik untuk menggambarkan pendapatan dan harga rumah.","The middle value":"Nilai tengah","Total items (n)":"Total item (n)","Value":"Nilai","Value × weight":"Nilai × bobot","Values (such as grades)":"Nilai (seperti nilai ujian)","Weight":"Bobot","Weighted average":"Rata-rata tertimbang","Weighted average calculator":"Kalkulator rata-rata tertimbang","Weights (such as credits or percentages)":"Bobot (seperti kredit atau persentase)","Weights must be zero or more, and not all zero.":"Bobot harus nol atau lebih, dan tidak boleh semuanya nol.","Without a population limit":"Tanpa batas populasi","z for this confidence":"z untuk tingkat keyakinan ini"}